Bonjour pouvez vous m’aider sur cela merci d’avance

Réponse :

Explications étape par étape

Bonjour

Puissances :

A = (49 x (-2)^5 x (-3)^(-2)) / (-7^3 x 16 x 3^(-3))

A = (7^2 x (-2)^5 x 3^(-2)) / (-7^3 x 2^4 x 3^(-3))

A = -(7^2 x 2^5 x 3^(-2)) / -(7^3 x 2^4 x 3^(-3))

A = 7^(2-3) x 2^(5-4) x 3^(-2+3)

A = 7^(-1) x 2^1 x 3^1

A = 7^(-1) x 2 x 3

A = 6/7

B = ((-5)^4 x 7^2 x (-2)^(-3)) / ((-4)^4 x (-1)^5 x 25)

B = (5^4 x 7^2 x -(2^(-3))) / ((2^2)^4 x -(1)^5 x 5^2)

B = -(5^4 x 7^2 x 2^(-3)) / -(2^(2x4) x 1^5 x 5^2)

B = 5^(4-2) x 7^2 x 2^(-3-8)

B = 5^2 x 7^2 x 2^(-11)

B = 25 x 49 x 1/2^11

B = 1225/2048

C = ((a^2b^4)^2/a^3)^(-3)

C = (a^(2x2)b^(4x2) / a^3)^(-3)

C = (a^4b^8 / a^3)^(-3)

C = (a^(4-3)b^8)^(-3)

C = (ab^8)^(-3)

C = a^(-3)b^(8x(-3))

C = a^(-3)b^(-24)

D = 0,0000000005 x 1004000000

D = 5 x 10^(-10) x 1,004 x 10^(-9)

D = 5 x 1,004 x 10^(-10-9)

D = 5,02 x 10^(-19)

E = 2^3/3^4 : 2^2/3^5

E = 2^3/3^4 x 3^5/2^2

E = 2^3/2^2 x 3^5/3^4

E = 2^(3-2) x 3^(5-4)

E = 2^1 x 3^1

E = 2 x 3

E = 6

F = (a^2b)^3 / [(-a)(-b)^2]

F = a^(2x3)b^3 / [(-a)b^2]

F = a^6/(-a) x b^3/b^2

F = -a^(6-1) x b^(3-2)

F = -a^5 x b^1

F = -a^5b