Bonjour , pouvez vous m'aider ? C'est sur les fractions . Merci

Bonsoir,

1) [tex]A=\dfrac{2}{9}-\dfrac{3}{4}\times\dfrac{5}{2}\\\\A=\dfrac{2}{9}-\dfrac{15}{8}\\\\A=\dfrac{16}{72}-\dfrac{135}{72}\\\\\boxed{A=-\dfrac{119}{72}}[/tex]

[tex]B=(\dfrac{2}{9}-\dfrac{3}{4})\times\dfrac{5}{2}\\\\B=(\dfrac{8}{36}-\dfrac{27}{36})\times\dfrac{5}{2}\\\\B=(-\dfrac{19}{36})\times\dfrac{5}{2}\\\\\boxed{B=-\dfrac{95}{72}}[/tex]

[tex]C=\dfrac{2}{9}-\dfrac{3}{4}:\dfrac{5}{2}\\\\C=\dfrac{2}{9}-\dfrac{3}{4}\times\dfrac{2}{5}\\\\C=\dfrac{2}{9}-\dfrac{6}{20}\\\\C=\dfrac{2}{9}-\dfrac{3}{10}\\\\C=\dfrac{20}{90}-\dfrac{27}{90}\\\\\boxed{C=-\dfrac{7}{90}}[/tex]

[tex]D=(\dfrac{2}{9}-\dfrac{3}{4}):\dfrac{5}{2}\\\\D=(\dfrac{2}{9}-\dfrac{3}{4})\times\dfrac{2}{5}\\\\D=(\dfrac{8}{36}-\dfrac{27}{36})\times\dfrac{2}{5}\\\\D=(-\dfrac{19}{36})\times\dfrac{2}{5}\\\\D=-\dfrac{38}{180}\\\\\boxed{D=-\dfrac{19}{90}}[/tex]


2) [tex]A+B+C+D=-\dfrac{119}{72}-\dfrac{95}{72}-\dfrac{7}{90}-\dfrac{19}{90}\\\\A+B+C+D=-\dfrac{214}{72}-\dfrac{26}{90}\\\\A+B+C+D=-\dfrac{107}{36}-\dfrac{26}{90}\\\\A+B+C+D=-\dfrac{535}{180}-\dfrac{52}{90}\\\\\boxed{A+B+C+D=-\dfrac{587}{180}}[/tex]